/*************************************************************************
 * 
 * Name:
 * 
 * PennKey: 
 * 
 * Execution: java LeapYear
 * 
 * Prints true if N corresponds to a leap year, and false otherwise. Assumes N
 * >= 1582, corresponding to a year in the Gregorian calendar.
 * 
 * A leap year takes place every four years. BUT! If the year is divisible by
 * 100, it's not actually a leap year. BUT! If the year is divisible by 400, it
 * is again a leap year!
 *
 *
 *************************************************************************/

public class LeapYear {
    public static void main(String[] args) {

        /*
         * Example of solving this without the use of variables.
         * Note how difficult this is to read without any variables
         * 
         * System.out.println("Is 2023 a leap year?");
         * System.out.println(((2023 % 4 == 0) && (2023 % 100 != 0)) || (2023 % 400 == 0));
         */
        int inputYear = 2023;
        boolean isLeapYear;

        // check if the year is divisible by 4
        isLeapYear = (inputYear % 4) == 0;

        // check that the year isn't divisible by 100
        isLeapYear = isLeapYear && (inputYear % 100) != 0;

        // if the year is divisible by 400, then it's a leap year anyway
        isLeapYear = isLeapYear || (inputYear % 400) == 0;

        System.out.println("Is " + inputYear + " a leap year?");
        System.out.println(isLeapYear);

    }
}